13104333403231 has 4 divisors (see below), whose sum is σ = 14976381032272. Its totient is φ = 11232285774192.

The previous prime is 13104333403223. The next prime is 13104333403247. The reversal of 13104333403231 is 13230433340131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13104333403231 - 2³ = 13104333403223 is a prime.

It is a super-2 number, since 2×13104333403231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104333403193 and 13104333403202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104333403201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936023814510 + ... + 936023814523.

It is an arithmetic number, because the mean of its divisors is an integer number (3744095258068).

Almost surely, 2^{13104333403231} is an apocalyptic number.

13104333403231 is a deficient number, since it is larger than the sum of its proper divisors (1872047629041).

13104333403231 is an equidigital number, since it uses as much as digits as its factorization.

13104333403231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1872047629040.

The product of its (nonzero) digits is 23328, while the sum is 31.

Adding to 13104333403231 its reverse (13230433340131), we get a palindrome (26334766743362).

The spelling of 13104333403231 in words is "thirteen trillion, one hundred four billion, three hundred thirty-three million, four hundred three thousand, two hundred thirty-one".