Base | Representation |
---|---|
bin | 1011111010110001011101… |
… | …0000110101101001010111 |
3 | 1201101202120200011121022110 |
4 | 2332230113100311221113 |
5 | 3204200134342310403 |
6 | 43512014300402103 |
7 | 2521520435661135 |
oct | 276542720655127 |
9 | 51352520147273 |
10 | 13104335510103 |
11 | 41a25768477a2 |
12 | 157785b546333 |
13 | 74096c76b346 |
14 | 334378bb4755 |
15 | 17ad1931c103 |
hex | beb17435a57 |
13104335510103 has 16 divisors (see below), whose sum is σ = 17579873675520. Its totient is φ = 8682511932864.
The previous prime is 13104335510081. The next prime is 13104335510141. The reversal of 13104335510103 is 30101553340131.
It is not a de Polignac number, because 13104335510103 - 214 = 13104335493719 is a prime.
It is a super-2 number, since 2×131043355101032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104335517103) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 52816843 + ... + 53064371.
It is an arithmetic number, because the mean of its divisors is an integer number (1098742104720).
Almost surely, 213104335510103 is an apocalyptic number.
13104335510103 is a deficient number, since it is larger than the sum of its proper divisors (4475538165417).
13104335510103 is a wasteful number, since it uses less digits than its factorization.
13104335510103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 355958.
The product of its (nonzero) digits is 8100, while the sum is 30.
Adding to 13104335510103 its reverse (30101553340131), we get a palindrome (43205888850234).
The spelling of 13104335510103 in words is "thirteen trillion, one hundred four billion, three hundred thirty-five million, five hundred ten thousand, one hundred three".
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