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131043412230149 is a prime number
BaseRepresentation
bin11101110010111011101100…
…000010010100000000000101
3122011222121221201012111112202
4131302323230002110000011
5114134003402012331044
61142412302411124245
736413400626264246
oct3562735402240005
9564877851174482
10131043412230149
1138833220a00181
1212845111743685
13581745781ba73
14245076c044ccd
151023b17167c4e
hex772eec094005

131043412230149 has 2 divisors, whose sum is σ = 131043412230150. Its totient is φ = 131043412230148.

The previous prime is 131043412230121. The next prime is 131043412230253. The reversal of 131043412230149 is 941032214340131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82863571261249 + 48179840968900 = 9102943^2 + 6941170^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131043412230149 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131043412230349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521706115074 + 65521706115075.

It is an arithmetic number, because the mean of its divisors is an integer number (65521706115075).

Almost surely, 2131043412230149 is an apocalyptic number.

It is an amenable number.

131043412230149 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043412230149 is an equidigital number, since it uses as much as digits as its factorization.

131043412230149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 62208, while the sum is 38.

The spelling of 131043412230149 in words is "one hundred thirty-one trillion, forty-three billion, four hundred twelve million, two hundred thirty thousand, one hundred forty-nine".