131043451510141 has 4 divisors (see below), whose sum is σ = 131052804421984. Its totient is φ = 131034098598300.

The previous prime is 131043451510067. The next prime is 131043451510183. The reversal of 131043451510141 is 141015154340131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131043451510141 - 2²¹ = 131043449412989 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131043451510097 and 131043451510106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131043451510841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4676434905 + ... + 4676462926.

It is an arithmetic number, because the mean of its divisors is an integer number (32763201105496).

Almost surely, 2^{131043451510141} is an apocalyptic number.

It is an amenable number.

131043451510141 is a deficient number, since it is larger than the sum of its proper divisors (9352911843).

131043451510141 is an equidigital number, since it uses as much as digits as its factorization.

131043451510141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9352911842.

The product of its (nonzero) digits is 14400, while the sum is 34.

The spelling of 131043451510141 in words is "one hundred thirty-one trillion, forty-three billion, four hundred fifty-one million, five hundred ten thousand, one hundred forty-one".