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131043451510217 is a prime number
BaseRepresentation
bin11101110010111011101110…
…011000001001110111001001
3122011222122001110010010200002
4131302323232120021313021
5114134003442041311332
61142412310333052345
736413401614203351
oct3562735630116711
9564878043103602
10131043451510217
1138833241099944
12128451229270b5
1358174629c29cc
14245077334bb61
151023b1a826562
hex772eee609dc9

131043451510217 has 2 divisors, whose sum is σ = 131043451510218. Its totient is φ = 131043451510216.

The previous prime is 131043451510201. The next prime is 131043451510277. The reversal of 131043451510217 is 712015154340131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130454339998921 + 589111511296 = 11421661^2 + 767536^2 .

It is a cyclic number.

It is not a de Polignac number, because 131043451510217 - 24 = 131043451510201 is a prime.

It is not a weakly prime, because it can be changed into another prime (131043451510277) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521725755108 + 65521725755109.

It is an arithmetic number, because the mean of its divisors is an integer number (65521725755109).

Almost surely, 2131043451510217 is an apocalyptic number.

It is an amenable number.

131043451510217 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043451510217 is an equidigital number, since it uses as much as digits as its factorization.

131043451510217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 38.

The spelling of 131043451510217 in words is "one hundred thirty-one trillion, forty-three billion, four hundred fifty-one million, five hundred ten thousand, two hundred seventeen".