Base | Representation |
---|---|
bin | 11101110010111011101110… |
… | …011000001001110110111001 |
3 | 122011222122001110010010122111 |
4 | 131302323232120021312321 |
5 | 114134003442041311301 |
6 | 1142412310333052321 |
7 | 36413401614203326 |
oct | 3562735630116671 |
9 | 564878043103574 |
10 | 131043451510201 |
11 | 3883324109992a |
12 | 128451229270a1 |
13 | 58174629c29b9 |
14 | 245077334bb4d |
15 | 1023b1a826551 |
hex | 772eee609db9 |
131043451510201 has 2 divisors, whose sum is σ = 131043451510202. Its totient is φ = 131043451510200.
The previous prime is 131043451510183. The next prime is 131043451510217. The reversal of 131043451510201 is 102015154340131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 116289824818176 + 14753626692025 = 10783776^2 + 3841045^2 .
It is a cyclic number.
It is not a de Polignac number, because 131043451510201 - 213 = 131043451502009 is a prime.
It is not a weakly prime, because it can be changed into another prime (131043451510291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521725755100 + 65521725755101.
It is an arithmetic number, because the mean of its divisors is an integer number (65521725755101).
Almost surely, 2131043451510201 is an apocalyptic number.
It is an amenable number.
131043451510201 is a deficient number, since it is larger than the sum of its proper divisors (1).
131043451510201 is an equidigital number, since it uses as much as digits as its factorization.
131043451510201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 131043451510201 in words is "one hundred thirty-one trillion, forty-three billion, four hundred fifty-one million, five hundred ten thousand, two hundred one".
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