Base | Representation |
---|---|
bin | 111101000001011010… |
… | …0100111001100101111 |
3 | 110112020200010021021011 |
4 | 1322002310213030233 |
5 | 4121334211132012 |
6 | 140111204250051 |
7 | 12316250223631 |
oct | 1720264471457 |
9 | 415220107234 |
10 | 131043849007 |
11 | 50636922365 |
12 | 214923a0927 |
13 | c485225476 |
14 | 64b1d8ca51 |
15 | 361e8071a7 |
hex | 1e82d2732f |
131043849007 has 2 divisors, whose sum is σ = 131043849008. Its totient is φ = 131043849006.
The previous prime is 131043848993. The next prime is 131043849017. The reversal of 131043849007 is 700948340131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131043849007 - 27 = 131043848879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131043849017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521924503 + 65521924504.
It is an arithmetic number, because the mean of its divisors is an integer number (65521924504).
Almost surely, 2131043849007 is an apocalyptic number.
131043849007 is a deficient number, since it is larger than the sum of its proper divisors (1).
131043849007 is an equidigital number, since it uses as much as digits as its factorization.
131043849007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 40.
The spelling of 131043849007 in words is "one hundred thirty-one billion, forty-three million, eight hundred forty-nine thousand, seven".
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