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1310439905545 = 51371913050957
BaseRepresentation
bin10011000100011100010…
…011100001100100001001
311122021110210212121022111
4103010130103201210021
5132432240103434140
62442001403022321
7163450631260651
oct23043423414411
94567423777274
101310439905545
11465833188801
12191b7b80a9a1
139675cc88a44
14475d5cdd361
152414a72a7ea
hex1311c4e1909

1310439905545 has 8 divisors (see below), whose sum is σ = 1584006193224. Its totient is φ = 1040699720064.

The previous prime is 1310439905519. The next prime is 1310439905581. The reversal of 1310439905545 is 5455099340131.

It can be written as a sum of positive squares in 4 ways, for example, as 365739495696 + 944700409849 = 604764^2 + 971957^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310439905545 - 237 = 1173000952073 is a prime.

It is a super-3 number, since 3×13104399055453 (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 956524794 + ... + 956526163.

It is an arithmetic number, because the mean of its divisors is an integer number (198000774153).

Almost surely, 21310439905545 is an apocalyptic number.

It is an amenable number.

1310439905545 is a deficient number, since it is larger than the sum of its proper divisors (273566287679).

1310439905545 is a wasteful number, since it uses less digits than its factorization.

1310439905545 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1913051099.

The product of its (nonzero) digits is 1458000, while the sum is 49.

The spelling of 1310439905545 in words is "one trillion, three hundred ten billion, four hundred thirty-nine million, nine hundred five thousand, five hundred forty-five".

Divisors: 1 5 137 685 1913050957 9565254785 262087981109 1310439905545