13104400032041 has 4 divisors (see below), whose sum is σ = 13115167822932. Its totient is φ = 13093632241152.

The previous prime is 13104400031981. The next prime is 13104400032047. The reversal of 13104400032041 is 14023000440131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4396972834816 + 8707427197225 = 2096896^2 + 2950835^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104400032041 - 2⁶ = 13104400031977 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104400031998 and 13104400032016.

It is not an unprimeable number, because it can be changed into a prime (13104400032047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5383893620 + ... + 5383896053.

It is an arithmetic number, because the mean of its divisors is an integer number (3278791955733).

Almost surely, 2^{13104400032041} is an apocalyptic number.

It is an amenable number.

13104400032041 is a deficient number, since it is larger than the sum of its proper divisors (10767790891).

13104400032041 is a wasteful number, since it uses less digits than its factorization.

13104400032041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10767790890.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13104400032041 its reverse (14023000440131), we get a palindrome (27127400472172).

The spelling of 13104400032041 in words is "thirteen trillion, one hundred four billion, four hundred million, thirty-two thousand, forty-one".