Base | Representation |
---|---|
bin | 11101110010111100001111… |
… | …000110011001110110100010 |
3 | 122011222200110201010222021110 |
4 | 131302330033012121312202 |
5 | 114134011103112132000 |
6 | 1142412441024004150 |
7 | 36413421331451100 |
oct | 3562741706316642 |
9 | 564880421128243 |
10 | 131044000505250 |
11 | 388334a2a7aa48 |
12 | 12845256760656 |
13 | 581751c670941 |
14 | 24507c6218c70 |
15 | 1023b4db1b850 |
hex | 772f0f199da2 |
131044000505250 has 192 divisors, whose sum is σ = 392761389376512. Its totient is φ = 28986691104000.
The previous prime is 131044000505203. The next prime is 131044000505261. The reversal of 131044000505250 is 52505000440131.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 56374027 + ... + 58652526.
It is an arithmetic number, because the mean of its divisors is an integer number (2045632236336).
Almost surely, 2131044000505250 is an apocalyptic number.
131044000505250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131044000505250 is an abundant number, since it is smaller than the sum of its proper divisors (261717388871262).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131044000505250 is a wasteful number, since it uses less digits than its factorization.
131044000505250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115026618 (or 115026601 counting only the distinct ones).
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 131044000505250 its reverse (52505000440131), we get a palindrome (183549000945381).
The spelling of 131044000505250 in words is "one hundred thirty-one trillion, forty-four billion, five hundred five thousand, two hundred fifty".
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