Base | Representation |
---|---|
bin | 1011111010110001101101… |
… | …1010011101110111101111 |
3 | 1201101202202112012022201111 |
4 | 2332230123122131313233 |
5 | 3204200310204034043 |
6 | 43512025225052451 |
7 | 2521522242565435 |
oct | 276543332356757 |
9 | 51352675168644 |
10 | 13104405143023 |
11 | 41a2602087a67 |
12 | 157787a927127 |
13 | 74098100ba5c |
14 | 33438413cd55 |
15 | 17ad204c409d |
hex | beb1b69ddef |
13104405143023 has 2 divisors, whose sum is σ = 13104405143024. Its totient is φ = 13104405143022.
The previous prime is 13104405142949. The next prime is 13104405143029. The reversal of 13104405143023 is 32034150440131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13104405143023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104405143029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552202571511 + 6552202571512.
It is an arithmetic number, because the mean of its divisors is an integer number (6552202571512).
Almost surely, 213104405143023 is an apocalyptic number.
13104405143023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104405143023 is an equidigital number, since it uses as much as digits as its factorization.
13104405143023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13104405143023 its reverse (32034150440131), we get a palindrome (45138555583154).
The spelling of 13104405143023 in words is "thirteen trillion, one hundred four billion, four hundred five million, one hundred forty-three thousand, twenty-three".
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