131044111102 has 4 divisors (see below), whose sum is σ = 196566166656. Its totient is φ = 65522055550.

The previous prime is 131044111097. The next prime is 131044111109. The reversal of 131044111102 is 201111440131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 201111440131 = 7 ⋅28730205733.

It is a self number, because there is not a number n which added to its sum of digits gives 131044111102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131044111109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32761027774 + ... + 32761027777.

It is an arithmetic number, because the mean of its divisors is an integer number (49141541664).

Almost surely, 2^131044111102 is an apocalyptic number.

131044111102 is a deficient number, since it is larger than the sum of its proper divisors (65522055554).

131044111102 is an equidigital number, since it uses as much as digits as its factorization.

131044111102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65522055553.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 131044111102 its reverse (201111440131), we get a palindrome (332155551233).

The spelling of 131044111102 in words is "one hundred thirty-one billion, forty-four million, one hundred eleven thousand, one hundred two".