Base | Representation |
---|---|
bin | 1011111010110001101111… |
… | …0010000100011010111011 |
3 | 1201101202202221211122222111 |
4 | 2332230123302010122323 |
5 | 3204200313300031420 |
6 | 43512030005433151 |
7 | 2521522346305111 |
oct | 276543362043273 |
9 | 51352687748874 |
10 | 13104411330235 |
11 | 41a2605623565 |
12 | 1577880a0b7b7 |
13 | 740982397024 |
14 | 334384cadab1 |
15 | 17ad20ce745a |
hex | beb1bc846bb |
13104411330235 has 8 divisors (see below), whose sum is σ = 15786481510656. Its totient is φ = 10442737121280.
The previous prime is 13104411330221. The next prime is 13104411330259. The reversal of 13104411330235 is 53203311440131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13104411330235 - 27 = 13104411330107 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13104411330197 and 13104411330206.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5098991451 + ... + 5098994020.
It is an arithmetic number, because the mean of its divisors is an integer number (1973310188832).
Almost surely, 213104411330235 is an apocalyptic number.
13104411330235 is a deficient number, since it is larger than the sum of its proper divisors (2682070180421).
13104411330235 is a wasteful number, since it uses less digits than its factorization.
13104411330235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10197985733.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 13104411330235 its reverse (53203311440131), we get a palindrome (66307722770366).
The spelling of 13104411330235 in words is "thirteen trillion, one hundred four billion, four hundred eleven million, three hundred thirty thousand, two hundred thirty-five".
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