13104411330431 has 2 divisors, whose sum is σ = 13104411330432. Its totient is φ = 13104411330430.

The previous prime is 13104411330421. The next prime is 13104411330449. The reversal of 13104411330431 is 13403311440131.

It is a weak prime.

It is an emirp because it is prime and its reverse (13403311440131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13104411330431 is a prime.

It is a super-2 number, since 2×13104411330431² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13104411330394 and 13104411330403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104411330421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552205665215 + 6552205665216.

It is an arithmetic number, because the mean of its divisors is an integer number (6552205665216).

Almost surely, 2^{13104411330431} is an apocalyptic number.

13104411330431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104411330431 is an equidigital number, since it uses as much as digits as its factorization.

13104411330431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 13104411330431 its reverse (13403311440131), we get a palindrome (26507722770562).

The spelling of 13104411330431 in words is "thirteen trillion, one hundred four billion, four hundred eleven million, three hundred thirty thousand, four hundred thirty-one".