1310442430001 has 4 divisors (see below), whose sum is σ = 1345859793012. Its totient is φ = 1275025066992.

The previous prime is 1310442429997. The next prime is 1310442430027. The reversal of 1310442430001 is 1000342440131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1104231078976 + 206211351025 = 1050824^2 + 454105^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310442430001 - 2² = 1310442429997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1310442430051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17708681450 + ... + 17708681523.

It is an arithmetic number, because the mean of its divisors is an integer number (336464948253).

Almost surely, 2^{1310442430001} is an apocalyptic number.

It is an amenable number.

1310442430001 is a deficient number, since it is larger than the sum of its proper divisors (35417363011).

1310442430001 is an equidigital number, since it uses as much as digits as its factorization.

1310442430001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35417363010.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1310442430001 its reverse (1000342440131), we get a palindrome (2310784870132).

The spelling of 1310442430001 in words is "one trillion, three hundred ten billion, four hundred forty-two million, four hundred thirty thousand, one".