Base | Representation |
---|---|
bin | 10011000100011100011… |
… | …101001100100110110110 |
3 | 11122021110222122102111111 |
4 | 103010130131030212312 |
5 | 132432241231104032 |
6 | 2442001533225234 |
7 | 163450661651242 |
oct | 23043435144666 |
9 | 4567428572444 |
10 | 1310442441142 |
11 | 46583465a83a |
12 | 191b8063221a |
13 | 96760665bb3 |
14 | 475d639d422 |
15 | 2414aa7bc47 |
hex | 1311c74c9b6 |
1310442441142 has 8 divisors (see below), whose sum is σ = 1965668723496. Its totient is φ = 655219533312.
The previous prime is 1310442441097. The next prime is 1310442441151. The reversal of 1310442441142 is 2411442440131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 671253 + ... + 1752559.
It is an arithmetic number, because the mean of its divisors is an integer number (245708590437).
Almost surely, 21310442441142 is an apocalyptic number.
1310442441142 is a deficient number, since it is larger than the sum of its proper divisors (655226282354).
1310442441142 is a wasteful number, since it uses less digits than its factorization.
1310442441142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1687262.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 1310442441142 its reverse (2411442440131), we get a palindrome (3721884881273).
The spelling of 1310442441142 in words is "one trillion, three hundred ten billion, four hundred forty-two million, four hundred forty-one thousand, one hundred forty-two".
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