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131044410104305 = 5157487342783479
BaseRepresentation
bin11101110010111100100111…
…100000111001100111110001
3122011222201112020212202112211
4131302330213200321213301
5114134012422441314210
61142412545415052121
736413434434132325
oct3562744740714761
9564881466782484
10131044410104305
1138833693201865
121284534b971041
135817586493449
14245082479b985
151023b74a7938a
hex772f278399f1

131044410104305 has 16 divisors (see below), whose sum is σ = 158579864651520. Its totient is φ = 103953888672192.

The previous prime is 131044410104303. The next prime is 131044410104317. The reversal of 131044410104305 is 503401014440131.

It is a cyclic number.

It is not a de Polignac number, because 131044410104305 - 21 = 131044410104303 is a prime.

It is not an unprimeable number, because it can be changed into a prime (131044410104303) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 171009445 + ... + 171774034.

It is an arithmetic number, because the mean of its divisors is an integer number (9911241540720).

Almost surely, 2131044410104305 is an apocalyptic number.

It is an amenable number.

131044410104305 is a deficient number, since it is larger than the sum of its proper divisors (27535454547215).

131044410104305 is a wasteful number, since it uses less digits than its factorization.

131044410104305 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 342784128.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 131044410104305 its reverse (503401014440131), we get a palindrome (634445424544436).

The spelling of 131044410104305 in words is "one hundred thirty-one trillion, forty-four billion, four hundred ten million, one hundred four thousand, three hundred five".

Divisors: 1 5 157 487 785 2435 76459 382295 342783479 1713917395 53817006203 166935554273 269085031015 834677771365 26208882020861 131044410104305