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131044410104317 is a prime number
BaseRepresentation
bin11101110010111100100111…
…100000111001100111111101
3122011222201112020212202120021
4131302330213200321213331
5114134012422441314232
61142412545415052141
736413434434132343
oct3562744740714775
9564881466782507
10131044410104317
1138833693201876
121284534b971051
135817586493458
14245082479b993
151023b74a79397
hex772f278399fd

131044410104317 has 2 divisors, whose sum is σ = 131044410104318. Its totient is φ = 131044410104316.

The previous prime is 131044410104303. The next prime is 131044410104339. The reversal of 131044410104317 is 713401014440131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99171542997081 + 31872867107236 = 9958491^2 + 5645606^2 .

It is a cyclic number.

It is not a de Polignac number, because 131044410104317 - 231 = 131042262620669 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131044410104417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522205052158 + 65522205052159.

It is an arithmetic number, because the mean of its divisors is an integer number (65522205052159).

Almost surely, 2131044410104317 is an apocalyptic number.

It is an amenable number.

131044410104317 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044410104317 is an equidigital number, since it uses as much as digits as its factorization.

131044410104317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16128, while the sum is 34.

Adding to 131044410104317 its reverse (713401014440131), we get a palindrome (844445424544448).

The spelling of 131044410104317 in words is "one hundred thirty-one trillion, forty-four billion, four hundred ten million, one hundred four thousand, three hundred seventeen".