Base | Representation |
---|---|
bin | 11101110010111100100111… |
… | …101001110011111000110000 |
3 | 122011222201112102021102200012 |
4 | 131302330213221303320300 |
5 | 114134012424041040422 |
6 | 1142412545541114052 |
7 | 36413434463031263 |
oct | 3562744751637060 |
9 | 564881472242605 |
10 | 131044412440112 |
11 | 38833694557786 |
12 | 128453506b8928 |
13 | 5817586b00692 |
14 | 2450824c08cda |
15 | 1023b74d8b4e2 |
hex | 772f27a73e30 |
131044412440112 has 10 divisors (see below), whose sum is σ = 253898549102748. Its totient is φ = 65522206220048.
The previous prime is 131044412440037. The next prime is 131044412440121. The reversal of 131044412440112 is 211044214440131.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4095137888738 + ... + 4095137888769.
Almost surely, 2131044412440112 is an apocalyptic number.
It is an amenable number.
131044412440112 is a deficient number, since it is larger than the sum of its proper divisors (122854136662636).
131044412440112 is an equidigital number, since it uses as much as digits as its factorization.
131044412440112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8190275777515 (or 8190275777509 counting only the distinct ones).
The product of its (nonzero) digits is 12288, while the sum is 32.
Adding to 131044412440112 its reverse (211044214440131), we get a palindrome (342088626880243).
The spelling of 131044412440112 in words is "one hundred thirty-one trillion, forty-four billion, four hundred twelve million, four hundred forty thousand, one hundred twelve".
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