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13104443433 = 34368147811
BaseRepresentation
bin11000011010001010…
…11111000000101001
31020211021022200220210
430031011133000221
5203314214142213
610004201411333
7642511634304
oct141505370051
936737280823
1013104443433
115615131344
122658799b49
13130ac0cb53
148c4595b3b
1551a6d30c3
hex30d15f029

13104443433 has 4 divisors (see below), whose sum is σ = 17472591248. Its totient is φ = 8736295620.

The previous prime is 13104443423. The next prime is 13104443441. The reversal of 13104443433 is 33434440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-13104443433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13104443433.

It is not an unprimeable number, because it can be changed into a prime (13104443413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2184073903 + ... + 2184073908.

It is an arithmetic number, because the mean of its divisors is an integer number (4368147812).

Almost surely, 213104443433 is an apocalyptic number.

It is an amenable number.

13104443433 is a deficient number, since it is larger than the sum of its proper divisors (4368147815).

13104443433 is an equidigital number, since it uses as much as digits as its factorization.

13104443433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4368147814.

The product of its (nonzero) digits is 20736, while the sum is 30.

Adding to 13104443433 its reverse (33434440131), we get a palindrome (46538883564).

The spelling of 13104443433 in words is "thirteen billion, one hundred four million, four hundred forty-three thousand, four hundred thirty-three".

Divisors: 1 3 4368147811 13104443433