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1310445113342 = 2655222556671
BaseRepresentation
bin10011000100011100100…
…111011000111111111110
311122021111011200012001212
4103010130213120333332
5132432242422111332
62442002110404422
7163451023451021
oct23043447307776
94567434605055
101310445113342
11465836115472
12191b81500712
1396761090291
14475d68971b8
152414ae088b2
hex1311c9d8ffe

1310445113342 has 4 divisors (see below), whose sum is σ = 1965667670016. Its totient is φ = 655222556670.

The previous prime is 1310445113297. The next prime is 1310445113353. The reversal of 1310445113342 is 2433115440131.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1310445113299 and 1310445113308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327611278334 + ... + 327611278337.

It is an arithmetic number, because the mean of its divisors is an integer number (491416917504).

Almost surely, 21310445113342 is an apocalyptic number.

1310445113342 is a deficient number, since it is larger than the sum of its proper divisors (655222556674).

1310445113342 is an equidigital number, since it uses as much as digits as its factorization.

1310445113342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655222556673.

The product of its (nonzero) digits is 17280, while the sum is 32.

The spelling of 1310445113342 in words is "one trillion, three hundred ten billion, four hundred forty-five million, one hundred thirteen thousand, three hundred forty-two".

Divisors: 1 2 655222556671 1310445113342