Base | Representation |
---|---|
bin | 1011111010110010001001… |
… | …0001011000110100010111 |
3 | 1201101210001112201000002020 |
4 | 2332230202101120310113 |
5 | 3204201024133003133 |
6 | 43512044455144223 |
7 | 2521525140565026 |
oct | 276544221306427 |
9 | 51353045630066 |
10 | 13104520203543 |
11 | 41a26610256aa |
12 | 15778b1375073 |
13 | 74099bac65c2 |
14 | 3343955308bd |
15 | 17ad2a6510b3 |
hex | beb22458d17 |
13104520203543 has 16 divisors (see below), whose sum is σ = 17732810239200. Its totient is φ = 8606569089024.
The previous prime is 13104520203539. The next prime is 13104520203641. The reversal of 13104520203543 is 34530202540131.
13104520203543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13104520203543 - 22 = 13104520203539 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104520203743) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34888218 + ... + 35261831.
It is an arithmetic number, because the mean of its divisors is an integer number (1108300639950).
Almost surely, 213104520203543 is an apocalyptic number.
13104520203543 is a deficient number, since it is larger than the sum of its proper divisors (4628290035657).
13104520203543 is an equidigital number, since it uses as much as digits as its factorization.
13104520203543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70150978.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 13104520203543 its reverse (34530202540131), we get a palindrome (47634722743674).
The spelling of 13104520203543 in words is "thirteen trillion, one hundred four billion, five hundred twenty million, two hundred three thousand, five hundred forty-three".
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