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13104524231543 is a prime number
BaseRepresentation
bin1011111010110010001010…
…0000110000001101110111
31201101210001211021122110102
42332230202200300031313
53204201031200402133
643512045121344315
72521525220042333
oct276544240601567
951353054248412
1013104524231543
1141a2663326a28
1215778b279809b
1374099c8a6b34
14334395c9c7c3
1517ad2ab997e8
hexbeb22830377

13104524231543 has 2 divisors, whose sum is σ = 13104524231544. Its totient is φ = 13104524231542.

The previous prime is 13104524231459. The next prime is 13104524231587. The reversal of 13104524231543 is 34513242540131.

13104524231543 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13104524231543 - 28 = 13104524231287 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104524231497 and 13104524231506.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104524531543) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552262115771 + 6552262115772.

It is an arithmetic number, because the mean of its divisors is an integer number (6552262115772).

Almost surely, 213104524231543 is an apocalyptic number.

13104524231543 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104524231543 is an equidigital number, since it uses as much as digits as its factorization.

13104524231543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 13104524231543 its reverse (34513242540131), we get a palindrome (47617766771674).

The spelling of 13104524231543 in words is "thirteen trillion, one hundred four billion, five hundred twenty-four million, two hundred thirty-one thousand, five hundred forty-three".