131045522111541 has 16 divisors (see below), whose sum is σ = 194141843913600. Its totient is φ = 87363533054304.

The previous prime is 131045522111533. The next prime is 131045522111549. The reversal of 131045522111541 is 145111225540131.

It is a happy number.

131045522111541 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 45 + 52 + 21 + 1 + 1 + 541 = 666.

It is an interprime number because it is at equal distance from previous prime (131045522111533) and next prime (131045522111549).

It is not a de Polignac number, because 131045522111541 - 2³ = 131045522111533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131045522111496 and 131045522111505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131045522111549) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13433065 + ... + 21036593.

It is an arithmetic number, because the mean of its divisors is an integer number (12133865244600).

Almost surely, 2^{131045522111541} is an apocalyptic number.

It is an amenable number.

131045522111541 is a deficient number, since it is larger than the sum of its proper divisors (63096321802059).

131045522111541 is an equidigital number, since it uses as much as digits as its factorization.

131045522111541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8241865 (or 8241859 counting only the distinct ones).

The product of its (nonzero) digits is 24000, while the sum is 36.

Adding to 131045522111541 its reverse (145111225540131), we get a palindrome (276156747651672).

The spelling of 131045522111541 in words is "one hundred thirty-one trillion, forty-five billion, five hundred twenty-two million, one hundred eleven thousand, five hundred forty-one".