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1310483973241 is a prime number
BaseRepresentation
bin10011000100011110111…
…011101000010001111001
311122021120212210110211101
4103010132323220101321
5132432332344120431
62442010015331401
7163452004660132
oct23043673502171
94567525713741
101310483973241
11465856047493
12191b92520b61
1396769147bc1
14475dbad0c89
152414e532961
hex1311eee8479

1310483973241 has 2 divisors, whose sum is σ = 1310483973242. Its totient is φ = 1310483973240.

The previous prime is 1310483973209. The next prime is 1310483973257. The reversal of 1310483973241 is 1423793840131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 661653723241 + 648830250000 = 813421^2 + 805500^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310483973241 - 25 = 1310483973209 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1310483973191 and 1310483973200.

It is not a weakly prime, because it can be changed into another prime (1310483973041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655241986620 + 655241986621.

It is an arithmetic number, because the mean of its divisors is an integer number (655241986621).

Almost surely, 21310483973241 is an apocalyptic number.

It is an amenable number.

1310483973241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310483973241 is an equidigital number, since it uses as much as digits as its factorization.

1310483973241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 435456, while the sum is 46.

The spelling of 1310483973241 in words is "one trillion, three hundred ten billion, four hundred eighty-three million, nine hundred seventy-three thousand, two hundred forty-one".