Base | Representation |
---|---|
bin | 10011000100011110111… |
… | …011101000010001011001 |
3 | 11122021120212210110210012 |
4 | 103010132323220101121 |
5 | 132432332344120314 |
6 | 2442010015331305 |
7 | 163452004660055 |
oct | 23043673502131 |
9 | 4567525713705 |
10 | 1310483973209 |
11 | 465856047464 |
12 | 191b92520b35 |
13 | 96769147b98 |
14 | 475dbad0c65 |
15 | 2414e53293e |
hex | 1311eee8459 |
1310483973209 has 2 divisors, whose sum is σ = 1310483973210. Its totient is φ = 1310483973208.
The previous prime is 1310483973187. The next prime is 1310483973241. The reversal of 1310483973209 is 9023793840131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1135929640000 + 174554333209 = 1065800^2 + 417797^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310483973209 - 236 = 1241764496473 is a prime.
It is not a weakly prime, because it can be changed into another prime (1310483972209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655241986604 + 655241986605.
It is an arithmetic number, because the mean of its divisors is an integer number (655241986605).
Almost surely, 21310483973209 is an apocalyptic number.
It is an amenable number.
1310483973209 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310483973209 is an equidigital number, since it uses as much as digits as its factorization.
1310483973209 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 50.
The spelling of 1310483973209 in words is "one trillion, three hundred ten billion, four hundred eighty-three million, nine hundred seventy-three thousand, two hundred nine".
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