Base | Representation |
---|---|
bin | 1011111010110100000101… |
… | …0101011010001010011001 |
3 | 1201101211101212100001102210 |
4 | 2332231001111122022121 |
5 | 3204203111041220241 |
6 | 43512212313145333 |
7 | 2521544066351223 |
oct | 276550125321231 |
9 | 51354355301383 |
10 | 13105041351321 |
11 | 41a28a9216747 |
12 | 1577a179bb249 |
13 | 740a52a7437a |
14 | 33440482d413 |
15 | 17ad5b295316 |
hex | beb4155a299 |
13105041351321 has 8 divisors (see below), whose sum is σ = 17803075043520. Its totient is φ = 8571850946672.
The previous prime is 13105041351319. The next prime is 13105041351371. The reversal of 13105041351321 is 12315314050131.
13105041351321 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13105041351321 - 21 = 13105041351319 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13105041351371) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41210821701 + ... + 41210822018.
It is an arithmetic number, because the mean of its divisors is an integer number (2225384380440).
Almost surely, 213105041351321 is an apocalyptic number.
It is an amenable number.
13105041351321 is a deficient number, since it is larger than the sum of its proper divisors (4698033692199).
13105041351321 is an equidigital number, since it uses as much as digits as its factorization.
13105041351321 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82421643775.
The product of its (nonzero) digits is 5400, while the sum is 30.
The spelling of 13105041351321 in words is "thirteen trillion, one hundred five billion, forty-one million, three hundred fifty-one thousand, three hundred twenty-one".
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