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131051041450493 is a prime number
BaseRepresentation
bin11101110011000010110010…
…110001011110100111111101
3122012000100122101221001101012
4131303002302301132213331
5114134120013102403433
61142420003423525005
736414060655503203
oct3563026261364775
9565010571831335
10131051041450493
113883648645035a
12128466a0759765
1358180a22b1728
142450c93393073
151023e11d22848
hex7730b2c5e9fd

131051041450493 has 2 divisors, whose sum is σ = 131051041450494. Its totient is φ = 131051041450492.

The previous prime is 131051041450489. The next prime is 131051041450543. The reversal of 131051041450493 is 394054140150131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103676830281124 + 27374211169369 = 10182182^2 + 5232037^2 .

It is a cyclic number.

It is not a de Polignac number, because 131051041450493 - 22 = 131051041450489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131051041450493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131051041456493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65525520725246 + 65525520725247.

It is an arithmetic number, because the mean of its divisors is an integer number (65525520725247).

Almost surely, 2131051041450493 is an apocalyptic number.

It is an amenable number.

131051041450493 is a deficient number, since it is larger than the sum of its proper divisors (1).

131051041450493 is an equidigital number, since it uses as much as digits as its factorization.

131051041450493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 131051041450493 in words is "one hundred thirty-one trillion, fifty-one billion, forty-one million, four hundred fifty thousand, four hundred ninety-three".