Base | Representation |
---|---|
bin | 11101110011000011001000… |
… | …010110110000001000001010 |
3 | 122012000101120122021020222122 |
4 | 131303003020112300020022 |
5 | 114134121233301334200 |
6 | 1142420103400451242 |
7 | 36414102643313504 |
oct | 3563031026601012 |
9 | 565011518236878 |
10 | 131051403543050 |
11 | 38836651884901 |
12 | 12846781a79b22 |
13 | 581812c30ca93 |
14 | 2450cc94cad74 |
15 | 1023e339e9385 |
hex | 7730c85b020a |
131051403543050 has 48 divisors (see below), whose sum is σ = 244865403444480. Its totient is φ = 52181928397440.
The previous prime is 131051403542987. The next prime is 131051403543121. The reversal of 131051403543050 is 50345304150131.
It is a self number, because there is not a number n which added to its sum of digits gives 131051403543050.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 165997646 + ... + 166785254.
It is an arithmetic number, because the mean of its divisors is an integer number (5101362571760).
Almost surely, 2131051403543050 is an apocalyptic number.
131051403543050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131051403543050 is a deficient number, since it is larger than the sum of its proper divisors (113813999901430).
131051403543050 is a wasteful number, since it uses less digits than its factorization.
131051403543050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 802767 (or 802762 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 131051403543050 its reverse (50345304150131), we get a palindrome (181396707693181).
The spelling of 131051403543050 in words is "one hundred thirty-one trillion, fifty-one billion, four hundred three million, five hundred forty-three thousand, fifty".
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