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1310532411413 = 7523174203431
BaseRepresentation
bin10011000100100001110…
…100011010000000010101
311122021201020221101111202
4103010201310122000111
5132432432244131123
62442014505442245
7163453133461241
oct23044164320025
94567636841452
101310532411413
11465880420835
12191ba67a0385
13967761a7444
14476042dd421
15241538eea28
hex13121d1a015

1310532411413 has 4 divisors (see below), whose sum is σ = 1310706622368. Its totient is φ = 1310358200460.

The previous prime is 1310532411371. The next prime is 1310532411431. The reversal of 1310532411413 is 3141142350131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310532411413 - 210 = 1310532410389 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310532411913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87094193 + ... + 87109238.

It is an arithmetic number, because the mean of its divisors is an integer number (327676655592).

Almost surely, 21310532411413 is an apocalyptic number.

It is an amenable number.

1310532411413 is a deficient number, since it is larger than the sum of its proper divisors (174210955).

1310532411413 is an equidigital number, since it uses as much as digits as its factorization.

1310532411413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 174210954.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 1310532411413 its reverse (3141142350131), we get a palindrome (4451674761544).

The spelling of 1310532411413 in words is "one trillion, three hundred ten billion, five hundred thirty-two million, four hundred eleven thousand, four hundred thirteen".

Divisors: 1 7523 174203431 1310532411413