Base | Representation |
---|---|
bin | 1011111010110101001010… |
… | …1010001111001011100011 |
3 | 1201101212011010021202102212 |
4 | 2332231102222033023203 |
5 | 3204204204444232120 |
6 | 43512301215232335 |
7 | 2521554226132436 |
oct | 276552252171343 |
9 | 51355133252385 |
10 | 13105332024035 |
11 | 41a2a382aa429 |
12 | 1577a992186ab |
13 | 740a9b057864 |
14 | 33443129581d |
15 | 17ad76a606c5 |
hex | beb52a8f2e3 |
13105332024035 has 8 divisors (see below), whose sum is σ = 15726420166560. Its totient is φ = 10484251127424.
The previous prime is 13105332024019. The next prime is 13105332024151. The reversal of 13105332024035 is 53042023350131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13105332024035 - 24 = 13105332024019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13105332023992 and 13105332024010.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3682139 + ... + 6306251.
It is an arithmetic number, because the mean of its divisors is an integer number (1965802520820).
Almost surely, 213105332024035 is an apocalyptic number.
13105332024035 is a deficient number, since it is larger than the sum of its proper divisors (2621088142525).
13105332024035 is an equidigital number, since it uses as much as digits as its factorization.
13105332024035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3622957.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 13105332024035 its reverse (53042023350131), we get a palindrome (66147355374166).
The spelling of 13105332024035 in words is "thirteen trillion, one hundred five billion, three hundred thirty-two million, twenty-four thousand, thirty-five".
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