1310537606047 has 4 divisors (see below), whose sum is σ = 1319333160600. Its totient is φ = 1301742051496.

The previous prime is 1310537606033. The next prime is 1310537606083. The reversal of 1310537606047 is 7406067350131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310537606047 is a prime.

It is a super-3 number, since 3×1310537606047³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310537605994 and 1310537606012.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310537606017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4397777053 + ... + 4397777350.

It is an arithmetic number, because the mean of its divisors is an integer number (329833290150).

Almost surely, 2^{1310537606047} is an apocalyptic number.

1310537606047 is a deficient number, since it is larger than the sum of its proper divisors (8795554553).

1310537606047 is an equidigital number, since it uses as much as digits as its factorization.

1310537606047 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8795554552.

The product of its (nonzero) digits is 317520, while the sum is 43.

The spelling of 1310537606047 in words is "one trillion, three hundred ten billion, five hundred thirty-seven million, six hundred six thousand, forty-seven".