Base | Representation |
---|---|
bin | 11101110011000101100011… |
… | …001001000011011011000111 |
3 | 122012000122021121202022012211 |
4 | 131303011203021003123013 |
5 | 114134142043101424201 |
6 | 1142421213204524251 |
7 | 36414224205361105 |
oct | 3563054311033307 |
9 | 565018247668184 |
10 | 131054000420551 |
11 | 3883776473735a |
12 | 128471876b0687 |
13 | 581845432b6a0 |
14 | 2451094358c75 |
15 | 10240369ae651 |
hex | 7731632436c7 |
131054000420551 has 32 divisors (see below), whose sum is σ = 143878644645120. Its totient is φ = 118623877691904.
The previous prime is 131054000420521. The next prime is 131054000420621. The reversal of 131054000420551 is 155024000450131.
It is not a de Polignac number, because 131054000420551 - 27 = 131054000420423 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131054000420521) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 13632992221 + ... + 13633001833.
It is an arithmetic number, because the mean of its divisors is an integer number (4496207645160).
Almost surely, 2131054000420551 is an apocalyptic number.
131054000420551 is a deficient number, since it is larger than the sum of its proper divisors (12824644224569).
131054000420551 is a wasteful number, since it uses less digits than its factorization.
131054000420551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18715.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 131054000420551 its reverse (155024000450131), we get a palindrome (286078000870682).
The spelling of 131054000420551 in words is "one hundred thirty-one trillion, fifty-four billion, four hundred twenty thousand, five hundred fifty-one".
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