Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …0011010111001110100001 |
3 | 1201101212022222001210001100 |
4 | 2332231112303113032201 |
5 | 3204204330242301103 |
6 | 43512312141025013 |
7 | 2521556031650550 |
oct | 276552663271641 |
9 | 51355288053040 |
10 | 13105401525153 |
11 | 41a2a7355a673 |
12 | 1577ab8555169 |
13 | 740aac580292 |
14 | 33443a5c7d97 |
15 | 17ad7cbdd5a3 |
hex | beb56cd73a1 |
13105401525153 has 48 divisors (see below), whose sum is σ = 22583595191040. Its totient is φ = 7160453194752.
The previous prime is 13105401525143. The next prime is 13105401525169. The reversal of 13105401525153 is 35152510450131.
13105401525153 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 540 + 15 + 2 + 51 + 53 = 666.
It is not a de Polignac number, because 13105401525153 - 25 = 13105401525121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13105401525113) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 2047125 + ... + 5513757.
It is an arithmetic number, because the mean of its divisors is an integer number (470491566480).
Almost surely, 213105401525153 is an apocalyptic number.
It is an amenable number.
13105401525153 is a deficient number, since it is larger than the sum of its proper divisors (9478193665887).
13105401525153 is a wasteful number, since it uses less digits than its factorization.
13105401525153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3469278 (or 3469275 counting only the distinct ones).
The product of its (nonzero) digits is 45000, while the sum is 36.
Adding to 13105401525153 its reverse (35152510450131), we get a palindrome (48257911975284).
The spelling of 13105401525153 in words is "thirteen trillion, one hundred five billion, four hundred one million, five hundred twenty-five thousand, one hundred fifty-three".
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