Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …1010101000010010001001 |
3 | 1201101212100002122120001011 |
4 | 2332231112322220102021 |
5 | 3204204331234230100 |
6 | 43512312245523521 |
7 | 2521556054103244 |
oct | 276552672502211 |
9 | 51355302576034 |
10 | 13105403430025 |
11 | 41a2a74640845 |
12 | 1577ab91135a1 |
13 | 740aaca9931a |
14 | 33443a96225b |
15 | 17ad7ce67bba |
hex | beb56ea8489 |
13105403430025 has 24 divisors (see below), whose sum is σ = 16320637555200. Its totient is φ = 10439212358400.
The previous prime is 13105403430001. The next prime is 13105403430107. The reversal of 13105403430025 is 52003430450131.
It is not a de Polignac number, because 13105403430025 - 27 = 13105403429897 is a prime.
It is a super-2 number, since 2×131054034300252 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 51790560 + ... + 52042990.
It is an arithmetic number, because the mean of its divisors is an integer number (680026564800).
Almost surely, 213105403430025 is an apocalyptic number.
It is an amenable number.
13105403430025 is a deficient number, since it is larger than the sum of its proper divisors (3215234125175).
13105403430025 is a wasteful number, since it uses less digits than its factorization.
13105403430025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 261369 (or 261364 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 13105403430025 its reverse (52003430450131), we get a palindrome (65108833880156).
The spelling of 13105403430025 in words is "thirteen trillion, one hundred five billion, four hundred three million, four hundred thirty thousand, twenty-five".
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