Search a number
-
+
13105403435132 = 2220333161134651
BaseRepresentation
bin1011111010110101011011…
…1010101001100001111100
31201101212100002122211001022
42332231112322221201330
53204204331234411012
643512312250003312
72521556054124161
oct276552672514174
951355302584038
1013105403435132
1141a2a74644668
121577ab9116538
13740aaca9b748
1433443a964068
1517ad7ce69472
hexbeb56ea987c

13105403435132 has 12 divisors (see below), whose sum is σ = 22935584096376. Its totient is φ = 6552379407600.

The previous prime is 13105403435093. The next prime is 13105403435147. The reversal of 13105403435132 is 23153430450131.

It is a junction number, because it is equal to n+sod(n) for n = 13105403435092 and 13105403435101.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 80485994 + ... + 80648657.

It is an arithmetic number, because the mean of its divisors is an integer number (1911298674698).

Almost surely, 213105403435132 is an apocalyptic number.

It is an amenable number.

13105403435132 is a deficient number, since it is larger than the sum of its proper divisors (9830180661244).

13105403435132 is a wasteful number, since it uses less digits than its factorization.

13105403435132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 161154988 (or 161154986 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 13105403435132 its reverse (23153430450131), we get a palindrome (36258833885263).

The spelling of 13105403435132 in words is "thirteen trillion, one hundred five billion, four hundred three million, four hundred thirty-five thousand, one hundred thirty-two".

Divisors: 1 2 4 20333 40666 81332 161134651 322269302 644538604 3276350858783 6552701717566 13105403435132