Base | Representation |
---|---|
bin | 1011111010110101011100… |
… | …0001100101100101011101 |
3 | 1201101212100020002020001002 |
4 | 2332231113001211211131 |
5 | 3204204332221111411 |
6 | 43512312353000045 |
7 | 2521556105441015 |
oct | 276552701454535 |
9 | 51355306066032 |
10 | 13105405253981 |
11 | 41a2a75677147 |
12 | 1577ab9853025 |
13 | 740ab02875a1 |
14 | 33443acb8c45 |
15 | 17ad7d1c833b |
hex | beb5706595d |
13105405253981 has 2 divisors, whose sum is σ = 13105405253982. Its totient is φ = 13105405253980.
The previous prime is 13105405253951. The next prime is 13105405254023. The reversal of 13105405253981 is 18935250450131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12968216501881 + 137188752100 = 3601141^2 + 370390^2 .
It is a cyclic number.
It is not a de Polignac number, because 13105405253981 - 222 = 13105401059677 is a prime.
It is a super-2 number, since 2×131054052539812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13105405253951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552702626990 + 6552702626991.
It is an arithmetic number, because the mean of its divisors is an integer number (6552702626991).
Almost surely, 213105405253981 is an apocalyptic number.
It is an amenable number.
13105405253981 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105405253981 is an equidigital number, since it uses as much as digits as its factorization.
13105405253981 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648000, while the sum is 47.
The spelling of 13105405253981 in words is "thirteen trillion, one hundred five billion, four hundred five million, two hundred fifty-three thousand, nine hundred eighty-one".
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