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13105405521350 = 252262108110427
BaseRepresentation
bin1011111010110101011100…
…0010100110110111000110
31201101212100020120210210122
42332231113002212313012
53204204332303140400
643512312402421542
72521556110633352
oct276552702466706
951355306523718
1013105405521350
1141a2a7583a00a
121577ab99618b2
13740ab034c1ac
1433443ad48462
1517ad7d22c685
hexbeb570a6dc6

13105405521350 has 12 divisors (see below), whose sum is σ = 24376054269804. Its totient is φ = 5242162208520.

The previous prime is 13105405521287. The next prime is 13105405521401. The reversal of 13105405521350 is 5312550450131.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13105405521350.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 131054055164 + ... + 131054055263.

It is an arithmetic number, because the mean of its divisors is an integer number (2031337855817).

Almost surely, 213105405521350 is an apocalyptic number.

13105405521350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13105405521350 is a deficient number, since it is larger than the sum of its proper divisors (11270648748454).

13105405521350 is a wasteful number, since it uses less digits than its factorization.

13105405521350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262108110439 (or 262108110434 counting only the distinct ones).

The product of its (nonzero) digits is 45000, while the sum is 35.

Adding to 13105405521350 its reverse (5312550450131), we get a palindrome (18417955971481).

The spelling of 13105405521350 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty-one thousand, three hundred fifty".

Divisors: 1 2 5 10 25 50 262108110427 524216220854 1310540552135 2621081104270 6552702760675 13105405521350