13105405530337 has 2 divisors, whose sum is σ = 13105405530338. Its totient is φ = 13105405530336.

The previous prime is 13105405530331. The next prime is 13105405530383. The reversal of 13105405530337 is 73303550450131.

13105405530337 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10122044058256 + 2983361472081 = 3181516^2 + 1727241^2 .

It is an emirp because it is prime and its reverse (73303550450131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13105405530337 - 2¹¹ = 13105405528289 is a prime.

It is a super-2 number, since 2×13105405530337² (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13105405530337.

It is not a weakly prime, because it can be changed into another prime (13105405530331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552702765168 + 6552702765169.

It is an arithmetic number, because the mean of its divisors is an integer number (6552702765169).

Almost surely, 2^{13105405530337} is an apocalyptic number.

It is an amenable number.

13105405530337 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105405530337 is an equidigital number, since it uses as much as digits as its factorization.

13105405530337 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 283500, while the sum is 40.

Adding to 13105405530337 its reverse (73303550450131), we get a palindrome (86408955980468).

The spelling of 13105405530337 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred thirty thousand, three hundred thirty-seven".