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13105405530383 is a prime number
BaseRepresentation
bin1011111010110101011100…
…0010101001000100001111
31201101212100020121021012012
42332231113002221010033
53204204332303433013
643512312402531435
72521556111001605
oct276552702510417
951355306537165
1013105405530383
1141a2a75845881
121577ab9966b7b
13740ab035333a
1433443ad4b875
1517ad7d2301a8
hexbeb570a910f

13105405530383 has 2 divisors, whose sum is σ = 13105405530384. Its totient is φ = 13105405530382.

The previous prime is 13105405530337. The next prime is 13105405530403. The reversal of 13105405530383 is 38303550450131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13105405530383 - 28 = 13105405530127 is a prime.

It is a super-2 number, since 2×131054055303832 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13105405530383.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13105405530313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552702765191 + 6552702765192.

It is an arithmetic number, because the mean of its divisors is an integer number (6552702765192).

Almost surely, 213105405530383 is an apocalyptic number.

13105405530383 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105405530383 is an equidigital number, since it uses as much as digits as its factorization.

13105405530383 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 13105405530383 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred thirty thousand, three hundred eighty-three".