13105405530403 has 2 divisors, whose sum is σ = 13105405530404. Its totient is φ = 13105405530402.

The previous prime is 13105405530383. The next prime is 13105405530467. The reversal of 13105405530403 is 30403550450131.

13105405530403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13105405530403 - 2¹³ = 13105405522211 is a prime.

It is not a weakly prime, because it can be changed into another prime (13105405536403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552702765201 + 6552702765202.

It is an arithmetic number, because the mean of its divisors is an integer number (6552702765202).

Almost surely, 2^{13105405530403} is an apocalyptic number.

13105405530403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105405530403 is an equidigital number, since it uses as much as digits as its factorization.

13105405530403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 13105405530403 its reverse (30403550450131), we get a palindrome (43508955980534).

The spelling of 13105405530403 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred thirty thousand, four hundred three".