13105411520053 has 4 divisors (see below), whose sum is σ = 13105424324160. Its totient is φ = 13105398715948.

The previous prime is 13105411520039. The next prime is 13105411520057. The reversal of 13105411520053 is 35002511450131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13105411520053 - 2⁵ = 13105411520021 is a prime.

It is a super-3 number, since 3×13105411520053³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13105411519997 and 13105411520024.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105411520057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4719325 + ... + 6962962.

It is an arithmetic number, because the mean of its divisors is an integer number (3276356081040).

Almost surely, 2^{13105411520053} is an apocalyptic number.

It is an amenable number.

13105411520053 is a deficient number, since it is larger than the sum of its proper divisors (12804107).

13105411520053 is a wasteful number, since it uses less digits than its factorization.

13105411520053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12804106.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 13105411520053 its reverse (35002511450131), we get a palindrome (48107922970184).

The spelling of 13105411520053 in words is "thirteen trillion, one hundred five billion, four hundred eleven million, five hundred twenty thousand, fifty-three".