13105433450131 has 4 divisors (see below), whose sum is σ = 14296836491064. Its totient is φ = 11914030409200.

The previous prime is 13105433450129. The next prime is 13105433450141.

13105433450131 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13105433450131 - 2¹ = 13105433450129 is a prime.

It is a super-2 number, since 2×13105433450131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13105433450101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 595701520450 + ... + 595701520471.

It is an arithmetic number, because the mean of its divisors is an integer number (3574209122766).

Almost surely, 2^{13105433450131} is an apocalyptic number.

13105433450131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

13105433450131 is a deficient number, since it is larger than the sum of its proper divisors (1191403040933).

13105433450131 is a wasteful number, since it uses less digits than its factorization.

13105433450131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1191403040932.

The product of its (nonzero) digits is 32400, while the sum is 34.

It can be divided in two parts, 1310543 and 3450131, that added together give a palindrome (4760674).

The spelling of 13105433450131 in words is "thirteen trillion, one hundred five billion, four hundred thirty-three million, four hundred fifty thousand, one hundred thirty-one".