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131058041 is a prime number
BaseRepresentation
bin1111100111111…
…00100101111001
3100010121102211112
413303330211321
5232022324131
621001010105
73150655262
oct763744571
9303542745
10131058041
1167a84934
1237a83935
13211c924a
1413597969
15b78c02b
hex7cfc979

131058041 has 2 divisors, whose sum is σ = 131058042. Its totient is φ = 131058040.

The previous prime is 131058019. The next prime is 131058089. The reversal of 131058041 is 140850131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93799225 + 37258816 = 9685^2 + 6104^2 .

It is a cyclic number.

It is not a de Polignac number, because 131058041 - 214 = 131041657 is a prime.

It is a super-2 number, since 2×1310580412 = 34352420221515362, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 131057998 and 131058016.

It is not a weakly prime, because it can be changed into another prime (131058091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65529020 + 65529021.

It is an arithmetic number, because the mean of its divisors is an integer number (65529021).

Almost surely, 2131058041 is an apocalyptic number.

It is an amenable number.

131058041 is a deficient number, since it is larger than the sum of its proper divisors (1).

131058041 is an equidigital number, since it uses as much as digits as its factorization.

131058041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480, while the sum is 23.

The square root of 131058041 is about 11448.0583943305. The cubic root of 131058041 is about 507.9503033307.

The spelling of 131058041 in words is "one hundred thirty-one million, fifty-eight thousand, forty-one".