Base | Representation |
---|---|
bin | 1011111010110111011011… |
… | …1101011011101001100111 |
3 | 1201101220201120020202021121 |
4 | 2332231312331123221213 |
5 | 3204211431401114443 |
6 | 43512441452354411 |
7 | 2521605302503432 |
oct | 276556675335147 |
9 | 51356646222247 |
10 | 13105941035623 |
11 | 41a3220052897 |
12 | 1578029175a07 |
13 | 740b6728a147 |
14 | 33448c106819 |
15 | 17adb025d4ed |
hex | beb76f5ba67 |
13105941035623 has 2 divisors, whose sum is σ = 13105941035624. Its totient is φ = 13105941035622.
The previous prime is 13105941035599. The next prime is 13105941035651. The reversal of 13105941035623 is 32653014950131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13105941035623 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13105941035623.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13105941035683) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552970517811 + 6552970517812.
It is an arithmetic number, because the mean of its divisors is an integer number (6552970517812).
Almost surely, 213105941035623 is an apocalyptic number.
13105941035623 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105941035623 is an equidigital number, since it uses as much as digits as its factorization.
13105941035623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 291600, while the sum is 43.
Adding to 13105941035623 its reverse (32653014950131), we get a palindrome (45758955985754).
The spelling of 13105941035623 in words is "thirteen trillion, one hundred five billion, nine hundred forty-one million, thirty-five thousand, six hundred twenty-three".
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