13106004010241 has 4 divisors (see below), whose sum is σ = 13528778333184. Its totient is φ = 12683229687300.

The previous prime is 13106004010223. The next prime is 13106004010261. The reversal of 13106004010241 is 14201040060131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13106004010241 is a prime.

It is a super-2 number, since 2×13106004010241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13106004010201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211387161425 + ... + 211387161486.

It is an arithmetic number, because the mean of its divisors is an integer number (3382194583296).

Almost surely, 2^{13106004010241} is an apocalyptic number.

It is an amenable number.

13106004010241 is a deficient number, since it is larger than the sum of its proper divisors (422774322943).

13106004010241 is an equidigital number, since it uses as much as digits as its factorization.

13106004010241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 422774322942.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13106004010241 its reverse (14201040060131), we get a palindrome (27307044070372).

The spelling of 13106004010241 in words is "thirteen trillion, one hundred six billion, four million, ten thousand, two hundred forty-one".