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13107005362465 = 57374485867499
BaseRepresentation
bin1011111010111011011001…
…1001100001000100100001
31201102000110201222011020021
42332232312121201010201
53204221121333044330
643513135232513441
72521643545232230
oct276566631410441
951360421864207
1013107005362465
1141a3716912353
1215782856ab881
13740ca692a841
1433454d5dab17
1517ae238e967a
hexbebb6661121

13107005362465 has 8 divisors (see below), whose sum is σ = 17975321640000. Its totient is φ = 8987660819952.

The previous prime is 13107005362457. The next prime is 13107005362523. The reversal of 13107005362465 is 56426350070131.

13107005362465 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13107005362465 - 23 = 13107005362457 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 187242933715 + ... + 187242933784.

It is an arithmetic number, because the mean of its divisors is an integer number (2246915205000).

Almost surely, 213107005362465 is an apocalyptic number.

It is an amenable number.

13107005362465 is a deficient number, since it is larger than the sum of its proper divisors (4868316277535).

13107005362465 is an equidigital number, since it uses as much as digits as its factorization.

13107005362465 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 374485867511.

The product of its (nonzero) digits is 453600, while the sum is 43.

The spelling of 13107005362465 in words is "thirteen trillion, one hundred seven billion, five million, three hundred sixty-two thousand, four hundred sixty-five".

Divisors: 1 5 7 35 374485867499 1872429337495 2621401072493 13107005362465