131070118411 has 2 divisors, whose sum is σ = 131070118412. Its totient is φ = 131070118410.

The previous prime is 131070118409. The next prime is 131070118463. The reversal of 131070118411 is 114811070131.

It is a weak prime.

It is an emirp because it is prime and its reverse (114811070131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131070118411 - 2¹ = 131070118409 is a prime.

It is a super-2 number, since 2×131070118411² (a number of 23 digits) contains 22 as substring.

Together with 131070118409, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 131070118411.

It is not a weakly prime, because it can be changed into another prime (131070158411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65535059205 + 65535059206.

It is an arithmetic number, because the mean of its divisors is an integer number (65535059206).

Almost surely, 2^131070118411 is an apocalyptic number.

131070118411 is a deficient number, since it is larger than the sum of its proper divisors (1).

131070118411 is an equidigital number, since it uses as much as digits as its factorization.

131070118411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 28.

Adding to 131070118411 its reverse (114811070131), we get a palindrome (245881188542).

The spelling of 131070118411 in words is "one hundred thirty-one billion, seventy million, one hundred eighteen thousand, four hundred eleven".