1310740026943 has 8 divisors (see below), whose sum is σ = 1354128316416. Its totient is φ = 1267420884600.

The previous prime is 1310740026941. The next prime is 1310740026977. The reversal of 1310740026943 is 3496200470131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1310740026943 - 2¹ = 1310740026941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1310740026896 and 1310740026905.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310740026941) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17248243 + ... + 17324068.

It is an arithmetic number, because the mean of its divisors is an integer number (169266039552).

Almost surely, 2^{1310740026943} is an apocalyptic number.

1310740026943 is a deficient number, since it is larger than the sum of its proper divisors (43388289473).

1310740026943 is a wasteful number, since it uses less digits than its factorization.

1310740026943 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34573565.

The product of its (nonzero) digits is 108864, while the sum is 40.

The spelling of 1310740026943 in words is "one trillion, three hundred ten billion, seven hundred forty million, twenty-six thousand, nine hundred forty-three".