Base | Representation |
---|---|
bin | 11101110011011001000010… |
… | …111100001000010100011111 |
3 | 122012002122022120212001010101 |
4 | 131303121002330020110133 |
5 | 114140012431324421203 |
6 | 1142434554401321531 |
7 | 36415565036346352 |
oct | 3563310274102437 |
9 | 565078276761111 |
10 | 131074934998303 |
11 | 3884562776548a |
12 | 1284b24a6362a7 |
13 | 581a40c5184ba |
14 | 24520bc7dc299 |
15 | 102485e7d741d |
hex | 773642f0851f |
131074934998303 has 2 divisors, whose sum is σ = 131074934998304. Its totient is φ = 131074934998302.
The previous prime is 131074934998213. The next prime is 131074934998309. The reversal of 131074934998303 is 303899439470131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131074934998303 - 233 = 131066345063711 is a prime.
It is a super-2 number, since 2×1310749349983032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131074934998309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65537467499151 + 65537467499152.
It is an arithmetic number, because the mean of its divisors is an integer number (65537467499152).
Almost surely, 2131074934998303 is an apocalyptic number.
131074934998303 is a deficient number, since it is larger than the sum of its proper divisors (1).
131074934998303 is an equidigital number, since it uses as much as digits as its factorization.
131074934998303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52907904, while the sum is 64.
The spelling of 131074934998303 in words is "one hundred thirty-one trillion, seventy-four billion, nine hundred thirty-four million, nine hundred ninety-eight thousand, three hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.098 sec. • engine limits •